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Informations about the package think-auth

think-auth

The ThinkPHP6+ Auth Package

安装

composer require zzstudio/think-auth

配置

生成配置

系统安装后会自动在 config 目录中生成 auth.php 的配置文件, 如果系统未生成可在命令行执行

快速生成配置文件

公共配置

导入数据表

think_ 为自定义的数据表前缀

原理

Auth权限认证是按规则进行认证。 在数据库中我们有

我们在规则表中定义权限规则, 在用户组表中定义用户与组的关系,在权限规则与组的关系表中定义权限组所拥有的权限。

下面举例说明:

我们要判断用户是否有显示一个操作按钮的权限, 首先定义一个规则, 在规则表中添加一个名为 show_button 的规则。 然后在用户组表添加一个用户组,定义这个用户组有show_button 的权限规则, 然后在用户与组关系表中定义 UID 为1 的用户 属于刚才这个的这个用户组。

使用

判断权限方法

或通过全局函数进行判断

Auth类也可以对节点进行认证,我们只要将规则名称,定义为节点名称就行了。 可以在公共控制器方法或中间件中进行验证了,以下为中间件的示例

可以通过命令行快速生成权限认证中间件

这个指令会 application/http/middleware 目录下面生成一个 Auth 中间件。

这时候我们可以在数据库中添加的节点规则, 格式为: “控制器名称/方法名称”

Auth 类 还可以多个规则一起认证 如:

表示 认证用户只要有rule1的权限或rule2的权限,只要有一个规则的权限,认证返回结果就为true 即认证通过。 默认多个权限的关系是 “or” 关系,也就是说多个权限中,只要有个权限通过则通过。 我们也可以定义为 “and” 关系

第三个参数指定为"and" 表示多个规则以and关系进行认证, 这时候多个规则同时通过认证才有权限。只要一个规则没有权限则就会返回false。

Auth认证,一个用户可以属于多个用户组。 比如我们对 show_button这个规则进行认证, 用户A 同时属于 用户组1 和用户组2 两个用户组 , 用户组1 没有show_button 规则权限, 但如果用户组2 有show_button 规则权限,则一样会权限认证通过。

Auth类还可以按用户属性进行判断权限, 比如 按照用户积分进行判断, 假设我们的用户表 (think_members) 有字段 score 记录了用户积分。 我在规则表添加规则时,定义规则表的condition 字段,condition字段是规则条件,默认为空 表示没有附加条件,用户组中只有规则 就通过认证。 如果定义了 condition字段,用户组中有规则不一定能通过认证,程序还会判断是否满足附加条件。 比如我们添加几条规则:

name字段:grade1 condition字段:{score}<100
name字段:grade2 condition字段:{score}>100 and {score}<200
name字段:grade3 condition字段:{score}>200 and {score}<300

这里 {score} 表示 think_members 表 中字段 score 的值。

那么这时候

$auth->check('grade1', uid) 是判断用户积分是不是0-100
$auth->check('grade2', uid) 判断用户积分是不是在100-200
$auth->check('grade3', uid) 判断用户积分是不是在200-300


All versions of think-auth with dependencies

PHP Build Version
Package Version
Requires php Version >=7.1.0
topthink/framework Version ^6.0
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